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Caution Review failedThe pull request is closed. WalkthroughThis PR updates the README entry for LeetCode problem 1653 and replaces the solution implementation: it adds an optimized O(n) Changes
Estimated code review effort🎯 4 (Complex) | ⏱️ ~45 minutes Possibly related PRs
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🚥 Pre-merge checks | ✅ 3✅ Passed checks (3 passed)
✏️ Tip: You can configure your own custom pre-merge checks in the settings. ✨ Finishing touches
🧪 Generate unit tests (beta)
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⚠️ Outside diff range comments (1)
src/main/java/codes/yam/leetcode/minimumdeletionstomakestringbalanced/Solution.java (1)
52-61:⚠️ Potential issue | 🟡 MinorNaive method returns
Integer.MAX_VALUEfor empty input.If
sis empty,minimumDeletionsNaivereturnsInteger.MAX_VALUEwhileminimumDeletionsreturns0. This is likely a non-issue given LeetCode constraints (1 ≤ s.length), but worth noting the behavioral divergence if these methods are ever compared in tests.
🧹 Nitpick comments (1)
src/main/java/codes/yam/leetcode/minimumdeletionstomakestringbalanced/Solution.java (1)
76-106: Consider O(1) space single-pass variant.The problem can be solved in O(n) time with O(1) space by maintaining a running
bCountand trackingmin(bCount + suffixA)in a single backward pass (or equivalently, a forward pass trackingbCountand computing min deletions on the fly). This would avoid the two auxiliary arrays.Not a blocker — the current solution is clear and correct.
Summary by CodeRabbit
Performance Improvements
Documentation
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